\newproblem{lay:4_3_6}{
  % Problem identification
	\begin{large}
	  \hspace{\fill}\newline
    \textbf{Lay, 4.3.6}
	\end{large}
	\\
  \ifthenelse{\boolean{identifyAuthor}}{\textit{Ana Pe\~na Gil, Jan. 19th 2014} \\}{}

  % Problem statement
	Determine whether the set $B=\{(1,2,-4),(-4,3,6)\}$ is a basis or 
	not for $\mathbb{R}^3$. If it is not,
	determine if it is linearly independent.\\
}{
  % Solution
	$B$ does not span $\mathbb{R}^3$ because it has only two vectors. 
	It needs exactly three independent vectors to span $\mathbb{R}^3$. 
	And therefore, it cannot be a basis for $\mathbb{R}^3$.\\
	The two vectors of the set $B$ are linearly independent because 
	none of them is a multiple of the other.  \\
}
\useproblem{lay:4_3_6}
\ifthenelse{\boolean{eachProblemInOnePage}}{\newpage}{}
